In this chapter, we provide RD Sharma Class 8 Solutions Chapter 9 Linear Equations in One Variable Ex 9.2 for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 8 Solutions Chapter 9 Linear Equations in One Variable Ex 9.2 Maths pdf, free RD Sharma Class 8 Solutions Chapter 9 Linear Equations in One Variable Ex 9.2 book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 8 |

Subject | Maths |

Chapter | Chapter 9 |

Chapter Name | Linear Equations in One Variable |

Exercise | Ex 9.2 |

**RD Sharma Solutions for Class 8 Chapter 9 Linear Equations in One Variable Ex 9.2** **Download PDF**

**Solve each of the following equations and also check your result in each case :****Question 1.****2x+53 = 3x – 10****Solution:**

2x+53 = 3x–101

By cross multiplication

⇒ 2x + 5 = 3 (3x – 10)

⇒ 2x + 5 = 9x – 30

⇒ 5 + 30 = 9x – 2x (By transposition)

⇒ 35 = 7x

⇒ x = 5

**Question 2.****a–83 = a–32****Solution:**

**Question 3.****7y+25 = 6y–511****Solution:**

**Question 4.****x – 2x + 2 – 163 x + 5 = 3 – 72 x.****Solution:**

**Question 5.****12 x + 7x – 6 = 7x + 14****Solution:**

**Question 6.****34 x + 4x = 78 + 6x – 6****Solution:**

**Question 7.****72 x – 52 x = 203 x + 10****Solution:**

72 x – 52 x = 203 x + 10

**Question 8.****6x+12 + 1 = 7x–33****Solution:**

**Question 9.****3a–23 + 2a+32 = a + 76****Solution:**

**Question 10.****x – x–12 = 1 – x–23****Solution:**

**Question 11.****3×4 – x–12 = x–23****Solution:**

**Question 12.****5×3 – x–14 = x–35****Solution:**

5×3 – x–14 = x–35

**Question 13.****Solution:**

**Question 14.****Solution:**

**Question 15.****Solution:**

**Question 16.****0.18 (5x – 4) = 0.5x + 0.8****Solution:**

**Question 17.****Solution:**

**Question 18.****Solution:**

**Question 19.****Solution:**

**Question 20.****Solution:**

**Question 21.****Solution:**

**Question 22.****Solution:**

**Question 23.****Solution:**

**Question 24.****(3x – 8) (3x + 2) – (4x – 11) (2x + 1) = (x – 3) (x + 7)****Solution:**

(3x – 8) (3x + 2) – (4x – 11) (2x + 1) = (x – 3) (x + 7)

⇒ (9x² + 6x – 24x – 16) – (8x² + 4x – 22x – 11) = x² + 7x – 3x – 21

⇒ 9x² + 6x – 24x – 16 – 8x² – 4x + 22x + 11 = x² + 4x – 21

⇒ 9x² – 8x² – x² + 6x – 24x + 22x – 4x – 4x = -21 + 16 – 11

⇒ 28x – 32x = -32 + 16

⇒ -4x = -16

⇒ x = 4

Verification:

L.H.S. = (3x – 8) (3x + 2) – (4x – 11) (2x + 1)

= (3 x 4 – 8) (3 x 4 + 2) – (4 x 4 – 11) (2 x 4 + 1)

= (12 – 8) (12 + 2) – (16 – 11) (8 + 1)

= 4 x 14 – 5 x 9 = 56 – 45 = 11

R.H.S. = (x – 3) (x + 7) = (4 – 3) (4 + 7) = 1 x 11 = 11

L.H.S. = R.H.S.

**Question 25.****[(2x + 3) + (x + 5)]² + [(2x + 3) – (x + 5)]² = 10x² + 92****Solution:**

[(2x + 3) + (x + 5)]² + [(2x + 3) – (x + 5)]² = 10x² + 92

⇒ (2x + 3 + x + 5)² + (2x + 3 – x – 5)² = 10x² + 92

⇒ (3x + 8)² + (x – 2)² = 10x² + 92

⇒ 9x² + 2 x 3x x 8 + 64 + x² – 2 x x x 2 + 4 = 10x² + 92

⇒ 9x² + 48x + 64 + x² – 4x + 4 = 10x² + 92

⇒ 9x² + x² – 10x² + 48x – 4x = 92 – 64 – 4

⇒ 44x = 24

**All Chapter RD Sharma Solutions For Class 8 Maths**

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**All Subject NCERT Solutions For Class 8**

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